Compute the value of the discriminant and give the number of real solutions to the quadratic equation?

Question

-3x^2 - 8x - 3 = 0
discriminant:
number of real solutions:

Answer 1

discriminant=b^2-ac
=64-4(-3)(-3)
=64-36
=28
so two real irrational solutions

Answer 2

if you see a quadratic equation in the general form is ax^2+bx+c=0 always the dscriminant will be: b^2-4*a*c so in your equation the discriminant will be (-8)^2-4*(-3)*(-3)=28. If the discriminant is >0 you will have only real solutions. If you graph this equation u will see that the function only crosses 2 times x axis, so the equation has 2 real solutions and no imaginary solutions

Answer 3

The discriminant is defined to be b^2 - 4ac (this is found under the square root symbol in the quadratic equation).

All you have to do is calculate b^2 - 4ac, given a = -3, b = -8, and c = -3

b^2 - 4ac = (-8)^2 - 4(-3)(-3) = 64 - 36 = 28

Your next step is to determine whether the discriminant is
(1) A perfect square
(2) Not a perfect square
(3) 0
(4) Negative

If it's a perfect square (excluding 0), then you have two rational roots.
If it's not a perfect square, you have two irrational roots.
If it's 0, you have one root.
And if it's negative, you have no roots (or two imaginary roots).

Since it's equal to 28, which is not a perfect square, then you have two irrational roots.

Answer 4

The discriminant is b^2-4ac. on your equation, a = 4 b = -4 c = a million (-4)^2-4(4)(a million) 16-16 0 --- which potential there is in undemanding words one genuine answer to the quadratic equation. *note: in case you plug the values and get a large decision more advantageous suited than 0, there are 2 ideas. in case you get a large decision cut back than 0, there are literally not any genuine ideas.