CaCl2(s) --> Ca2+ (aq) + 2Cl-(aq) delta H= -81.5
an 11.0 g sample of CaCl2 is deissolved in 125 g of water, with both substances at 25.0 degrees celcius. calcultae the final temperature of the solution assuming no heat is lost to the surroundings and assuming the solution has a specific heat capacity of 4.18J/degrees C g
thnx!
2006-12-07 09:57:13 · 1 answers · asked by m a 3 in Science & Mathematics ➔ Chemistry
i just need help in getting it started and what equation i shud use...
2006-12-07 10:01:10 · update #1
You can figure out the heat liberated by figuring out how many moles 11g of CaCl2 is since you know you get 81.5 kJ of heat per mole of CaCl2 (heat is liberated since dH is negative)
The use the equation
Q=m*Cp*dT
to figure out the temperature change. Q is the heat you calculated in the first part. m is the mass of water. and Cp is the specific heat of water.
2006-12-07 10:14:06 · answer #1 · answered by Duluth06ChE 3 · 0⤊ 0⤋