Find the logarithm using the change of base formula
log3 10
2006-12-07 08:52:18 · 5 answers · asked by mixedbeauty2007 2 in Science & Mathematics ➔ Mathematics
log 10 / log 3
where "log" means any logarithmic function (log base 10, or ln, usually)
2006-12-07 08:54:06 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋
Which logarithm? briggsian or naperian?
log_3 10=ln 10 / ln 3 = log 10 / log 3=1/ log 3
2006-12-07 16:57:18 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
The change of base formula goes as follows:
log[base c](a) = {log[base b]a} / {log[base b](c)}
In other words, we can change the base to whatever we want to. Let's make it base 10 (remember, logs by default are base 10, if there's no base stated).
(log 10)/(log 3)
Or, quite simply,
1/(log 3)
log 10 = 1 because it's asking, "10 to the what equals 10?"
2006-12-07 16:56:44 · answer #3 · answered by Puggy 7 · 0⤊ 0⤋
logarithm identity: log3 (10)=log(10)/log(3) = 2.096
2006-12-07 17:00:39 · answer #4 · answered by B0NER 3 · 0⤊ 0⤋
1/log 3 base 10
1/0.4771
=2.096
2006-12-07 16:56:13 · answer #5 · answered by raj 7 · 0⤊ 0⤋