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if 500 gm of dextrose are dissolved in 600ml os water, with the final vol. being 1000ml,what is the % strength of the dextrose in the sol.?

2006-12-07 08:03:01 · 3 answers · asked by rimple 1 in Science & Mathematics Chemistry

500gm:600ml=xgm :1000ml
600x=1000*500
600x=500000
x=500000/600
x=833gm
833/1000*100=83.3%
am i right?

2006-12-07 08:05:38 · update #1

3 answers

if 500 gm of dextrose are dissolved in 600ml os water, with the final vol. being 1000ml,what is the % strength of the dextrose in the sol.?

500 plus 600 does not equal 1000 ml Duh?
500/1000 = _____your answer in Percentage

You are wrong wrong wrong!!!

2006-12-07 08:08:33 · answer #1 · answered by god knows and sees else Yahoo 6 · 0 0

Are you sure you need the % strength? Do you mean concentration?

your choices are

500g/600ml = (0.083 g dextrose)/(ml water)

500g/1000ml (0.5 g dextrose)/(ml solution)

convert mass of dextrose to moles
and get
moles dextrose/L solution =Molarity of the solution

I'm not familiar with % strength. Strength by what measure? moles? mass? volume? Maybe you can provide clarification.

2006-12-07 16:28:27 · answer #2 · answered by rm 3 · 0 0

sure dear u are wronge

strength is a concentration unit and it is equal to
s=M(molarity)*M.wt(molecular weight) "low 1"
or
s=N(normality)*eq.wt(equivalent weight) "low 2"

now let's know what is Molarity mean and how to calculate it
molarity is also a concentraion unit it is refer to the number of moles of solute"dextrose" per littre "solution"
so
M=no of moles / volume (littre) "low 3"

no of moles of dextrose which have structure of (C6H12O6) calculate as the following
no of moles = wt/molecular weight
the MOlecular weight of dextrose =[(6*12)+(1*12)+(6*16)=180
so number of moles = 500/180=2.7
now back to calcualte the molarity from the above low no--(3)

M=n/volume(littre)
so M=2.7/1=2.7
the strength now is equal to from low (1)
s= M *M.wt
s= 2.7*180=486

2006-12-07 16:31:28 · answer #3 · answered by ch_yaso 2 · 0 0

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