what is the pH for OH- = 10(power -2) M?

3 ⤊

what is the pH for OH- = 10(power -2) M?

2006-12-07 07:34:42 · 3 answers · asked by Valray C 1 in Science & Mathematics ➔ Chemistry

3 answers

pOH is 2
use -log[OH]
plug 10^-2 into the OH and put in ur calculator. answer should be 2. woops i put the wrong thing in my calculator lol

2006-12-07 07:38:15 · answer #1 · answered by Sparkle 3 · 0⤊ 0⤋

pOH - -log[OH-] = -log(10^-2) = 2

At 25 oC pH + pOH = 14, so:

pH = 14 - pOH = 14 - 2 = 12

2006-12-07 07:46:45 · answer #2 · answered by Dimos F 4 · 1⤊ 0⤋

pH = -log[H+]
pOH = -log [OH-]
pH + pOH = 14

[H+] x [OH-] = 1x10^(-14)

pOH = -log(1x10^-2) = 2
pH + 2 = 14
pH = 12

or
[H+] = [1x10^(-14)]/ [OH-] =
[1x10^(-14)]/ [1x10^-2]= 1x10^(-12)
pH=-log(1x10^(-12)) = 12

2006-12-07 07:42:17 · answer #3 · answered by rm 3 · 2⤊ 0⤋