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A(x)= x sqrt x+3

2006-12-07 04:45:45 · 2 answers · asked by Brittany 1 in Science & Mathematics Mathematics

2 answers

To determine the critical numbers, you must find where A'(x) is equal to 0 or where A'(x) is undefined.

A'(x) = sqrt(x) + x(1/2)(1/sqrt(x))
A'(x) = sqrt(x) + x / [2(sqrt(x)]

Now, put it under a common denominator.

A'(x) = (2x + x)/[2(sqrt(x)]
A'(x) = (3/2) [x/sqrt(x)]
A'(x) = (3/2) x^(1/2)

To find the critical number, equate this to 0
(3/2) x^(1/2) = 0
x^(1/2) = 0
Therefore, x = 0

2006-12-07 04:56:40 · answer #1 · answered by Puggy 7 · 0 0

it is
(x^3/2)+3
diff wrt x
(3/2)x^1/2
take this equal to zero
u get
x=0
as critical number

2006-12-07 12:50:46 · answer #2 · answered by Dupinder jeet kaur k 2 · 0 0

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