and is it show on TV like the world cup draw?
x...X...x15yr old girl UKx...X...x
2006-12-07 04:27:12 · 6 answers · asked by Anonymous in Sports ➔ Football ➔ UEFA Champions League
the draw for the knock-out stage of the 2006-2007 UEFA Champions' League will takes place on Friday, 15 December 2006 @ 12:00 CET at UEFA headquarters in Nyon, Switzerland. the first leg will be played on 20 & 21 February 2007 while the return leg will be played on 06 & 07 March 2007.
the teams line-up for the knock-out stage of the 2006-2007 UEFA Champions' League is now completed:
Group winners:
Chelsea - ENGLAND
Bayern Munich - GERMANY
Liverpool - ENGLAND
Valencia CF - SPAIN
Olympique Lyonnaise - FRANCE
Manchester United - ENGLAND
Arsenal - ENGLAND
AC Milan - ITALY
Group runners-up:
FC Barcelona - defending champions - SPAIN
Internazionale Milan - ITALY
PSV Eindhoven - NETHERLANDS
AS Roma - ITALY
Real Madrid CF - SPAIN
Glasgow Celtic - SCOTLAND
FC Porto - PORTUGAL
LOSC Lille Metropole - FRANCE
the group winners will play against the other group runners-up & the winner of these match-ups will progress to the quarter-finals.
teams from the same country & also those teams who have played each other in the group stage will NOT be drawn together. the group runners-up will host the first match while the group winners will host the return match.
2006-12-08 01:05:38 · answer #1 · answered by foongwk140804 7 · 0⤊ 0⤋
The draw for the quarter-finals, semi-finals and final will be held on Friday, 14 March 2008 at 14:00 CET in Nyon, Switzerland.
2016-05-23 03:48:46 · answer #2 · answered by ? 4 · 0⤊ 0⤋
December 15 2006, if you have Eurosport you could watch there but on uefa.com you have live draw too!!!!!!
2006-12-07 05:03:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
i think in next year in middle of 2007
2006-12-07 04:34:49 · answer #4 · answered by Roller 2 · 0⤊ 0⤋
yes sky sports or eurosport next friday,
2006-12-07 06:02:04 · answer #5 · answered by DAVID C 2 · 0⤊ 0⤋
it's on friday 15th of december.
2006-12-07 04:59:15 · answer #6 · answered by jonsinher 4 · 0⤊ 0⤋