the total number of atoms in 1.00g of Ca CO3 (MM=100.0 g/mol) is?

Question

a) 2.41x 10^23 b) 2.41 x10^22 c) 3.01x 10^23 d) 1.81 x 10^22 e) 3.01x 10^22

Answer 1

Avogadro's number is 6.023* 10^23 per mole.

So:

1.00g * (mole/100.0g) * (6.023 * 10^23/mole)= 6.023 * 10^21 moles

Now, each molecule of CaCO3 has 5 atoms, so:

5 * 6.023 ^21 = 3.01 * 10^22

Done.

Answer 2

there are avogadro's number of Molucules in 100 g CaCO3
there are avogadro's number of Molucules / 100 in 1 g CaCO3
There are 5 atoms in each molecule

avogadro's number of Molucules / 100 * 5 = #atoms

Avogadro's number = 6.0221415 × 1023

((6.0221415 * (10^23)) / 100) * 5 = 3.01107075 × 10^22

Answer 3

Take the mass (1.00 g) and divide that by the MM to give you the number of moles. Then, multiply that answer by Avogadro's number togive you the molecules of CaCO3 that you have.

Finally, each molecule of CaCO3 has 5 atoms in it, so multiply the number of molecules by 5 to get your final answer.

Answer 4

always to obtain the number of atoms use the following equation

number of atoms= number of moles x 6x10^23(avogadro constant)

Answer 5

E