Solve for x.?

Question

log4 (5x+1) =2

Answer 1

it is 4^2 = 5x + 1
16 = 5x + 1
5x = 15
x = 3

thats your answers for log base 4

Have a nice day ...
:)

Answer 2

Your first step is to convert it to exponential form. You can do this by performing the following steps.

(1) The base of the log becomes the base of the exponent.
(2) The inside of the log becomes the answer.
(3) Whatever remains becomes the power.

In this case, the log of the base is 4, so our form will be
4^(?) = ?

The inside of the log becomes the answer. In this case, the answer is to the right of the equal sign, so we replace that with 5x+1.

4^(?) = 5x + 1

Whatever remains is the power. In this case, the remaining thing we haven't touched is the 2. This becomes the power.

4^2 = 5x + 1

Now we solve as normal.

16 = 5x + 1
15 = 5x
Therefore, x = 3.

Answer 3

4(5x+1)=100
20x+4 =100
20x=96
x=24/5

Answer 4

4^2=16, eliminate the log.
16=5x+1
15=5x
x=3

Answer 5

I won't answer your question straight up, but I'll tell you how to solve.

Log equations can be rearranged to make more sense. In your case, we could just as well say 4^2 = x. So you need to make your (5x+1) = 4^2.

Answer 6

5x+1=4^2
5x=16-1
=1
x=15/5=3

Answer 7

remember that 4^(2)=16...ie log4 (16) = 2

log4(5x+1)=log4(16)
5x+1=16..............taking antilog on both sides
5x=15
x=3

Answer 8

if the 4 is a base then
16=5x+1
15=5x
x=3

if base is 10
then
10^2=20x+4
100=20x+4
96=20x
x=96/20=4,8

Answer 9

is that log 4?

anyway, exponentate (to power 4, if it is log 4) both sides. Than it is an algebraic equation since the exponent will cancel the log on the left hand side.

Answer 10

x equals infinity. it's always the right answer.