Solve for X.?

0 ⤊

log3 (x) + log3 (x-2) = 1

2006-12-07 03:45:43 · 3 answers · asked by susan h 1 in Science & Mathematics ➔ Mathematics

3 answers

logx(x-2)base 3=1
x(x-2)=3
x^2-2x-3=0
(x-3)(x+1)=0
x=3 or -1

2006-12-07 03:49:21 · answer #1 · answered by raj 7 · 0⤊ 0⤋

log3 x + log3 (x-2) = 1
log3 x(x-2) = 1
x(x-2) = 3^1
xÂ² - 2x = 3
xÂ² - 2x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 or x = -1

BUT.... x=-1 doesn't work in the original equation, so it's only x=3.

2006-12-07 11:54:40 · answer #2 · answered by Jim Burnell 6 · 0⤊ 0⤋

if the base is 3 then
x^2-2x-3=0
find the roots.

2006-12-07 12:05:57 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋