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2 answers

Use the formula: pH = pKa + log10 ( [salt]/[acid]]
In this case: pH = 4.7 + log10 ( 2/1) = 5.0

2006-12-10 23:55:32 · answer #1 · answered by cordefr 7 · 0 0

The easiest equation to use is the Henderson-Haselbalch equation which says:

pH = pKa + log ([conjugate base]/[conjugate acid])

Your [conjugate base] is 2.00 M and your [conjugate acid] is 1.00 M. Look up or calculate the pKa (-log Ka) for acetic acid, and solve the equation for the pH.

2006-12-07 11:53:29 · answer #2 · answered by hcbiochem 7 · 0 0

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