where can i get the arrangement of (a+b) whole cube?

Question

please tell the websites or you yourself explain by showing its diagrams

Answer 1

I am giving you.
(a+b)^3=a^3+3a^2b+3ab^2+b^3
or
(a+b)^3= a^3+b^3+3ab(a+b)

Answer 2

a+b whole cube is aaa+bbb+3aab+3abb. To make a model make a cubical box of side say 8units where a=3 and b=5(a+b=8). Now make a cube of side 3units and another cube of side 5units. Make a cuboid of dimensions 3b,a,a and another cuboid of dimensions 3a,b,b. Now place these in the cube of Side 8 units. They will fit in perfectly. I hope I have solved your problem. All the best!

Answer 3

Using binomial theorem:

(a+b)^3=3C0(a^3) + 3C1(a^2b) + 3C2(ab^2) + 3C3(b^3)
=a^3 + 3ba^2 + 3 ab^2 + b^3

easy way out:
(a+b)^3=(a+b)(a+b)(a+b)
multiply any two
=>(a+b)(a^2 + 2ab + b^2)
Now multiply both brackets:

=>a^3 + 2a^b + ab^2 +ba^2 + 2ab^2 + b^3
=>a^3+ b^3 + 3ab^2 + 3a^2b

Answer 4

(a+b)^3=(a+b)^2(a+b)
You must be knowing formula of square of (a+b)
=(a^2+2ab+b^2)(a+b) (multiply these two factors)
=a^3+3a^2b+3ab^2+b^3

Answer 5

So simple.


(a+b)^3=a^3+3a^2b+3ab^2+b^3
or
(a+b)^3= a^3+b^3+3ab(a+b)

Answer 6

(a+b)^3= a^3+ b^3+3ab^2+3a^2b.
you can laso use this for simple arithmetic
(a+b)^3= a^3+b^3+3ab(a+b)