The sales decay for a product is given by S=50,000e^-0.1x, where S is the weekly sales (in dollars) and x represents the number of weeks since the end of the campign. HOw many weeks will pass before sale dop below 15,000?
2006-12-07 03:18:38 · 3 answers · asked by defman88 1 in Science & Mathematics ➔ Mathematics
15k = 50k e^(-0.1x)
Divide both sides by 50k:
0.3 = e^(-0.1x)
Take the ln of both sides:
ln 0.3 = -0.1x
Divide both sides by -0.1:
x = ln 0.3/-0.1 = 12.03 weeks
2006-12-07 03:23:23 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
Substitute 15,000 for S. Divide both sides by 50,000 and take the natural logarithm. Once you solve it, x = -ln(0.3) / 0.1 or 12.0397
2006-12-07 11:27:44 · answer #2 · answered by i_amswift03 1 · 0⤊ 0⤋
15,000 = 50,000 e^-0.1X
15,000/50000 = e^-0.1X
ln(15,000/50,000) = -0.1x
x=-10*ln(15,000/50,000) = 12
2006-12-07 11:30:36 · answer #3 · answered by David H 4 · 0⤊ 0⤋