In 0.100 mol of tetramethylhydrazine, (CH3) 2N2 (CH3), there are?

Question

a) 1.08 x 10(24)atoms b) 6.02 x 10(23)mol c) 6.02 x 10(24)mol d)1.82 x 10(23) atoms e) 6.02 x 10(23) atoms

Answer 1

The formula of Tetramethyl Hydrazine is wrongly mentioned. It will be (CH3)2N--N(CH3)2 or simply (CH3)4N2

1 mole of any substance contains 6.02* 10^23 molecules.

hence, 0.1 mol of (CH3)2N--N(CH3)2 will contain 6.02* 10^23*0.1=6.02* 10^22 molecules.

each atom of (CH3)2N--N(CH3)2 has 18 atoms.

so 6.02* 10^22 molecules of (CH3)2N--N(CH3)2 has 6.02* 10^22*18 = 1.08*10^(24) atoms.

Hence option A is correct.

Answer 2

I think you have the formula wrong there, but the answer is a.

1 mol = 6.02 E23
0.1 mol = 6.02 E22
you have 18 atoms in the molecule, so

6.02 E22 x 18 = 1.08E24

Answer 3

First the formula for tetramethylhydrazine is (CH3)2 -N2-(CH3)2. There are 18 atoms in each molecule or 18 moles of atoms in one mole of the compound. In 0.100 mole there would be 1.8 moles of atoms. 1.8 x 6.02E23 = 1.08E24. (A) is the correct answer. (6.02E23 = 6.02 x 10^23 = one mole)