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14 answers

1/2n+1.5m

2006-12-07 02:28:05 · answer #1 · answered by Anonymous · 1 0

First and foremost, it might pay to ask if you are SURE you typed this problem correctly; did you intend to use two different variable names (n and m)?

If so, then the only like terms are the three 'm' terms, whose coefficients we must add together:

1/2n + 2/3m +1/2m + 1/3m
= (1/2)n + (2/3 + 1/2 + 1/3)m
= (1/2)n + (1 + 1/2)m
= (1/2)n + (3/2)m

On the other hand, if all the variables were supposed to be just 'm', then the coefficients add much more simply, by grouping the 'halves' terms together, then the 'thirds' terms.

1/2m + 2/3m +1/2m + 1/3m
= (1/2 + 1/2)m + (2/3 + 1/3)m
= 1m + 1m
= 2m

Hope this helps!

2006-12-07 02:31:34 · answer #2 · answered by Tim GNO 3 · 0 0

2/3m can add with 1/3m
2/3m+1/3m=3/3m

3/3m+1/2m=6/6m+3/6m
=9/6m
=3/2m

you need to make the denominator equal in order to + the equation

3/2m+1/2n or in decimal 1.5m+0.5n

2006-12-07 02:43:04 · answer #3 · answered by tru m 1 · 0 0

1/2n + 1 1/2m

2006-12-07 02:30:21 · answer #4 · answered by Tag 1 · 0 0

1/2n+1 1/2m

2006-12-07 02:48:28 · answer #5 · answered by Ranna Renni 2 · 0 0

3m + 1/2n

2006-12-07 02:38:08 · answer #6 · answered by Dom 3 · 0 0

1/2n + 2/3m +1/2m + 1/3m =(1/2n + 1/2m) +(2/3m + 1/3m)
=(1/2n + 1/2m) +(3/3m)
=(1/2n + 1/2m) +m
=[(n+m)/2]+(2m/2)
=(n+3m)/2
or=n/2+3m/2
or=1/2n + 3/2m
or=0.5n+1.5m

that all...................

2006-12-07 03:05:47 · answer #7 · answered by San 2 · 0 0

1/2n+(2/3+1/2+1/3)m

2006-12-07 02:44:37 · answer #8 · answered by Anonymous · 0 0

1/2 n + 3/2 m

because 2/3 + 1/3 = 1 and 1 + 1/2 = 3/2

2006-12-07 02:28:31 · answer #9 · answered by anton3s 3 · 0 0

if that 1/2n is m the answer would be

= 12/6m or 2/m

2006-12-07 02:31:08 · answer #10 · answered by (,") Verns (",) 3 · 0 0

Assuming you mean (1/2)n and so on

(1/2)n+((4+3+2)/6)m
or(1/2)n+(9/6)m
(1/2)n+(3/2)m

2006-12-07 02:29:07 · answer #11 · answered by math_teacher_02 2 · 0 0

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