How would you factor this?

Question

How would you factor:

x^2 - 6x + 9

Answer 1

x^2-3x-3x+9
=x(x-3)-3(x-3)
=(x-3)(x-3)

Answer 2

the answer is (x-3)(x-3)

( )( )

here's an easy way....

there are 2 bracket,since there are x to the power of 2,then fill each bracket with an x

(x )(x )

then look at the number without any unknown.
square root of that number is........

fill each bracket with square root of nine,that is 3

(x 3)(x 3)

then,look at the signs in the equation,its X^2-6x+9.
so,its (-)(+) right?
when negative meets positive,it will be negative.
so,put negative sign between x and three

and the answer is(x-3)(x-3).

try this method on another question.

Answer 3

Find two numbers that multiply to 9 and add to -6, then put them into this form (x+a)(x+b).

They are -3 and -3 in this case.

So the factored form is (x-3)(x-3).

Answer 4

that is a perfect square trinomial..
so the factor is the sq root of the polynomial
1st term:get the sq root of the 1st term
sq root x^2=x
2nd term:get the sq root of the 3rd term
sq root 9=3

answer:
(x-3)^2 [copy the sign of the 2nd term] [square the binomial]

Answer 5

(x-3)^2

Answer 6

x² - 6x + 9

(x - 3)(x - 3)

- - - - - - -s-

Answer 7

x^2-6x+9
x^2-3x-3x+9
x(x-3)-3(x-3)
(x-3)(x-3)