there are none,
the two inequalities are equivalent.
i.e., any number which makes the first true will make the second true. the converse has no counterexamples either, as any number which makes the second true will make the first true.
2006-12-07 01:27:46
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answer #1
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answered by Anonymous
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A counterexample to p-->q, you need to find a case where p is true and q is not. So your counterexample would have to be n such that
4n-8>52 and n<=15 --->
4n-8>52 and 4n<=60 --->
4n-8>52 and 4n-8<=52 --->
impossible.
2006-12-07 01:35:51
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answer #2
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answered by Anonymous
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4n - 8 > 52 <=> 4n > 60 <=> n > 15
=> There is no counterexample.
2006-12-07 01:29:02
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answer #3
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answered by anton3s 3
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Let
p = 4n - 8 > 52
q = n > 15
p=>q : 4n - 8 > 52, then n > 15.
The counter example is '4n - 8 < 52, then n > 15'
This is a counter example because, p=>q is true, if p is true and false if p is false.
This means p=>q is true, irrespective of truth of q.
I hope that it is clear now.
All the best.
2006-12-07 01:31:37
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answer #4
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answered by Paritosh Vasava 3
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n> 15
2006-12-07 01:37:49
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answer #5
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answered by Angel Girl 5
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if n<15 then 4n-8<52 so no counter
2006-12-07 01:28:59
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answer #6
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answered by raj 7
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4n - 8 > 52
4n - 8 + 8 > 52 + 8
4n > 60
4n /4 > 60 / 4
n > 15
The answer is n > 15
- - - - - -s-
2006-12-07 02:08:41
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answer #7
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answered by SAMUEL D 7
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2016-11-24 20:49:30
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answer #8
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answered by ? 4
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4n - 8 > 52
4n > 60
n > 15
Therefore, for this inequality to be true, n must be greater than 15.
2006-12-07 01:29:28
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answer #9
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answered by thejackallhaslanded 2
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There is no counter example for that equation. Variable n is indeed greater than 15.
2006-12-07 01:32:37
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answer #10
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answered by kennethau03 2
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