H2CO3 is a weak acid. What is the chemical equation for its disscociation in water?
Can you help me write the chemical equation for the neutralization of the strong acid HCI by the strong base KOH?
In the question above does any body know what the spectator ions in the equation is?
2006-12-07 01:07:38 · 5 answers · asked by cetinnovations 1 in Science & Mathematics ➔ Chemistry
In aqueous solution, carbonic acid H2CO3, dissociates into hydronium ion and hydrogen carbonate (sometimes called bicarbonate) ion:
H2CO3 <====> H+ + HCO3-
The bicarbonate ion can undergo a second dissociation as follows:
HCO3- <====> H+ + CO3-2
For your second question:
HCl + KOH ======> KCl + H2O
spectator ions would be K+ and Cl- which, although I've written them as the salt above, really are in the ionic form as K+ and Cl- in solution.
2006-12-07 01:13:33 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋
H2CO3 + H2O <--> HCo3- + H3O+
HCl (aq) + KOH (aq) -->HOH (water) + KCl (aq).
K+ and Cl- are the spectator ions because they remain dissolved in the water--we write "KCl (aq)" but really they haven't formed a new molecule as long as they're aqueous.
2006-12-07 01:10:21 · answer #2 · answered by Amy F 5 · 1⤊ 0⤋
Fe3PO4+H2O -->Fe+3 + 2H+1 + OH-1 + 3PO4-3
2016-05-23 03:24:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
H2CO3 <__---> 2H+ + CO3 (2-)
HCl + KOH ------> KCl + H2O
2006-12-07 01:12:37 · answer #4 · answered by Anonymous · 1⤊ 0⤋
I'd assume it would be:
H2CO3+H20= H4C04
HCL+KOH= KCL+H20
2006-12-07 01:10:04 · answer #5 · answered by Anonymous · 0⤊ 1⤋