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The empirical formula is the simplest ratio of elements in a compound. The procedure to determine the simplest ratio is to find the number of moles of each element in the compound, divide each by the least number of moles and assign whole number ratios to each element.
For glucose:
Elements % moles ratio CH2O
C 40 || x1/12= 3.33 || 3.33/3.33 = 1
H 6.7|| x1/1 = 6.7 || 6.7/3.33 = 2
O 53.3||x 1/16= 3.33 || 3.33/3.33= 2
Molecular formula for glucose is 6 x the above empirical formula or C6H12O6. || Lines added to separate the calculations.

2006-12-07 00:24:26 · answer #1 · answered by docrider28 4 · 0 0

It's the simplest formula for a compound, showing the smallest whole number ratio of atoms. eg the molecular formula for glucose C4 H12 O6, the empirical would be C H2 O.
I can't remember how to work them out, i remember that example is all.

2006-12-06 23:40:42 · answer #2 · answered by Phil C 2 · 0 0

The subscripts interior the chemical formula aspect out the mole ratio of the elements. interior the empirical, the subscripts are the smallest entire huge form ratio. type of moles = mass ÷ mass of one million mole 111.6g of iron and 40 8.0g of oxygen type of moles of Fe = 111.6 ÷ fifty 5.8 = 2 type of moles of O = 40 8 ÷ 16 = 3 The subscripts are 2 and three. Fe2O3 8.0g of sulfur and eight.0g of oxygen type of moles of S = 8 ÷ 32 = 0.25 type of moles of O = 8 ÷ 16 = 0.5 to examine the smallest entire huge form ratio, divide each and each and every huge form by the smallest huge form. 0.25 ÷ 0.25 = a million 0.5 ÷ 0.25 = 2 The subscripts are a million and a couple of. SO2

2016-11-24 20:44:34 · answer #3 · answered by Anonymous · 0 0

It is a formula derived from experimental results, and is therefore not based on theory but fact

2006-12-06 23:32:26 · answer #4 · answered by Anonymous · 0 0

this is the simplest formula a compound could have.

2006-12-07 09:53:07 · answer #5 · answered by tokziez 1 · 0 0

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