With powers the general rule is:
a^(b+c) = (a^b) x (a^c)
for example
2^7 = 2 x 2 x 2 x 2 x 2 x 2 x 2
which is the same as
(2 x 2 x 2) x (2 x 2 x 2 x 2) = (2^3) x (2^4)
with your question
2(p+q) = (2^p) x (2^q) = x + y
2006-12-06 22:23:22
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answer #1
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answered by jansahar 3
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recall how to find all solutions to X^2 + Y^2 =Z^2 since it similar. ... Express x and y in terms of p, q, and r. The fact that we have three equations or8x3y2z2 + 5x2yz3 - 3xyz + 4x2yz3. 9. Express 7.1 10-6 in standard notation. ... f(x) = 10x4 + ax3 + bx2 + cx + 3, what is true about p and q? ...orHence for X,Y à Z show that {KWP(x, y)|x à XÃy à Y} à P2(Z) satisfies the rules for ... [Hint: define q\prec p on primes of this form if q < p and there are ...dont know
x _ ,y ) ~ - ~ + '" + ~-~ Nouvelle trigonometrie, ou l'on trouve le moyen ... Example' F 2x~ - 4x q- 1 1 1 1 = (x-- l?(x- 2) (x- 1)2 q-x- 1 -} x- 2' P 5x2-- ...
p1, p2, ... and q1, q2, ... being rational. We suppose that the roots of (1) and (2) are x1, x2, ... and y1, y2, ..., where x and y are x1 and y1, ...Given four points (0,0), (x1,y1), (x2,y2), and (x3,y3) in the plane, ... For example, with p = 3 and q = 5 we need r to be a divisor of 214 - 1 ...
2006-12-06 21:57:33
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answer #2
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answered by i am not a lovely girl i am cute 4
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One of the laws of exponents says that :
a^p * a^q = a^(p + q)
Replacing 'a' with '2' gives :
2^p * 2^q = 2^(p + q)
But x = 2^p and y = 2^q.
Therefore, 2^(p + q) = xy.
2006-12-06 22:38:51
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answer #3
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answered by falzoon 7
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Ooh looks tricky! Are you stuck on your maths homework?! I remember doing that at school- Nightmare!! hehe
2006-12-06 22:00:20
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answer #5
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answered by beaujolais_fairy_blossom 2
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