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6 answers

With powers the general rule is:

a^(b+c) = (a^b) x (a^c)

for example

2^7 = 2 x 2 x 2 x 2 x 2 x 2 x 2

which is the same as

(2 x 2 x 2) x (2 x 2 x 2 x 2) = (2^3) x (2^4)

with your question

2(p+q) = (2^p) x (2^q) = x + y

2006-12-06 22:23:22 · answer #1 · answered by jansahar 3 · 0 0

recall how to find all solutions to X^2 + Y^2 =Z^2 since it similar. ... Express x and y in terms of p, q, and r. The fact that we have three equations or8x3y2z2 + 5x2yz3 - 3xyz + 4x2yz3. 9. Express 7.1 10-6 in standard notation. ... f(x) = 10x4 + ax3 + bx2 + cx + 3, what is true about p and q? ...orHence for X,Y Ì Z show that {KWP(x, y)|x Î XÙy Î Y} Ì P2(Z) satisfies the rules for ... [Hint: define q\prec p on primes of this form if q < p and there are ...dont know
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2006-12-06 21:57:33 · answer #2 · answered by i am not a lovely girl i am cute 4 · 0 0

One of the laws of exponents says that :
a^p * a^q = a^(p + q)

Replacing 'a' with '2' gives :
2^p * 2^q = 2^(p + q)

But x = 2^p and y = 2^q.
Therefore, 2^(p + q) = xy.

2006-12-06 22:38:51 · answer #3 · answered by falzoon 7 · 0 0

2^(p+q)
=2^p . 2^q
= xy

2006-12-07 14:47:14 · answer #4 · answered by Kemmy 6 · 0 0

Ooh looks tricky! Are you stuck on your maths homework?! I remember doing that at school- Nightmare!! hehe

2006-12-06 22:00:20 · answer #5 · answered by beaujolais_fairy_blossom 2 · 0 0

2ys-ur-2ys-ub-ic-ur-2ys-for me.

2006-12-06 22:05:27 · answer #6 · answered by ShayMonYou 3 · 0 0

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