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Is it either:
-pi/3
pi/3
pi/6
-pi/6

2006-12-06 18:56:21 · 7 answers · asked by Apples 2 in Science & Mathematics Mathematics

7 answers

It is the angle whose sin = -1/2.

That's a 30-degree angle in the 4th quadrant, so it's -pi/6.

2006-12-06 18:58:37 · answer #1 · answered by Jim Burnell 6 · 0 0

The expression "sin^-1 (-1/2)" means "Give me an angle in either the first or fourth quadrant whose sine is -1/2." The sin-1 function ALWAYS gives an angle between -pi/2 and pi/2, inclusive. There will always be one unique angle in this interval that works.

In this case, the appropriate angle is -pi/6, because sin (-pi/6) = -1/2, and -pi/2 <= -pi/6 <= pi/2.

2006-12-06 22:43:21 · answer #2 · answered by Anonymous · 0 0

The three preceding answers have given you only one solution, namely - pi/6.

However, there are TWO solutions, one in the third, and one in the fourth quadrant.

Recall that sin (pi/6) = 1/2.

But sin (-x) = - sin (x); so sin (-pi/6) = -1/2. (Everyone's answer, so far.)

Also, sin (pi - y) = sin (y) --- no matter what the sign of y. So, if y = -pi/6, sin (pi + pi/6) = sin (-pi/6) = -1/2.

So, the two solutions are: - pi/6 (4th quadrant) and 7pi/6 or -5pi/6 (3rd quadrant).

Live long and prosper.

2006-12-06 19:02:50 · answer #3 · answered by Dr Spock 6 · 0 2

-30 degrees. Which would be -pi/6 radians.

2006-12-06 19:00:39 · answer #4 · answered by Anonymous · 0 0

x = sin^-1 ( -1/2)
use sin on both sides
sin(x) = sin ( sin^-1 (-1/2) )
sin(x) = -1/2
x = -pi/6

2006-12-06 19:13:54 · answer #5 · answered by jimmy 1 · 0 0

- pi/6

2006-12-06 19:00:00 · answer #6 · answered by Mikey 2 · 0 0

-pi/6

2006-12-06 20:41:09 · answer #7 · answered by Sohil V 1 · 0 0

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