It is the angle whose sin = -1/2.
That's a 30-degree angle in the 4th quadrant, so it's -pi/6.
2006-12-06 18:58:37
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answer #1
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answered by Jim Burnell 6
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The expression "sin^-1 (-1/2)" means "Give me an angle in either the first or fourth quadrant whose sine is -1/2." The sin-1 function ALWAYS gives an angle between -pi/2 and pi/2, inclusive. There will always be one unique angle in this interval that works.
In this case, the appropriate angle is -pi/6, because sin (-pi/6) = -1/2, and -pi/2 <= -pi/6 <= pi/2.
2006-12-06 22:43:21
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answer #2
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answered by Anonymous
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The three preceding answers have given you only one solution, namely - pi/6.
However, there are TWO solutions, one in the third, and one in the fourth quadrant.
Recall that sin (pi/6) = 1/2.
But sin (-x) = - sin (x); so sin (-pi/6) = -1/2. (Everyone's answer, so far.)
Also, sin (pi - y) = sin (y) --- no matter what the sign of y. So, if y = -pi/6, sin (pi + pi/6) = sin (-pi/6) = -1/2.
So, the two solutions are: - pi/6 (4th quadrant) and 7pi/6 or -5pi/6 (3rd quadrant).
Live long and prosper.
2006-12-06 19:02:50
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answer #3
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answered by Dr Spock 6
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-30 degrees. Which would be -pi/6 radians.
2006-12-06 19:00:39
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answer #4
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answered by Anonymous
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x = sin^-1 ( -1/2)
use sin on both sides
sin(x) = sin ( sin^-1 (-1/2) )
sin(x) = -1/2
x = -pi/6
2006-12-06 19:13:54
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answer #5
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answered by jimmy 1
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- pi/6
2006-12-06 19:00:00
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answer #6
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answered by Mikey 2
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-pi/6
2006-12-06 20:41:09
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answer #7
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answered by Sohil V 1
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