1/7x^7 - 19
42x^5
x^7 + 12
7x^6 + 2
Thanks in advance. Can't quite figure out this one :/
2006-12-06 18:32:17 · 4 answers · asked by Apples 2 in Science & Mathematics ➔ Mathematics
The answer is the third one, x^7 + 12.
To figure this out, you can just take the derivative of the four expressions you have, and see which one has its derivative equal to 7x^6.
The derivative of 1/7x^7 - 19 is x^6, so that doesn't work.
The derivative of 42x^5 is 210x^4, so that doesn't work.
The derivative of 7x^6 + 2 is 42x^5, so that one doesn't work either.
The derivative of x^7 + 12 is 7x^6, so this is the answer you want.
2006-12-06 22:49:51 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x^7+12
x^7 derivative is 7x^6
12 derivative is 0
hence the answer is 7x^6+0
2006-12-07 02:42:38 · answer #2 · answered by stanley810 2 · 0⤊ 0⤋
There is only 1 answer. As scythian indicates, it's x^7 + 12.
2006-12-07 02:41:39 · answer #3 · answered by mathlete1 3 · 0⤊ 0⤋
x^7 + 12. 12 is a constant.
2006-12-07 02:34:30 · answer #4 · answered by Scythian1950 7 · 1⤊ 0⤋