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There are seven(7) sacks
and in each sack their are seven(7) cats
and in every cat she have seven(7) kittens
Q: How many feet has it all?

*Assuming that the cats and kittens are all normal having
4feet = 1cat or 1kitten

2006-12-06 17:31:28 · 12 answers · asked by Konsehal Mikol 2 in Science & Mathematics Mathematics

and in every kitten their are seven(7) mouses/mices

thats only warm up!!!! goodluck

2006-12-06 17:52:08 · update #1

12 answers

( ( 7 * 7 cats ) + ( 7 * 7 * 7 kittens ) ) * 4 legs =
( 49 + 343 ) * 4 = 1568 legs

2006-12-06 17:33:02 · answer #1 · answered by TankAnswer 4 · 0 0

hmm...can it be??..

7 sacks

7 cats

7 kittens

then assuming that each cat or kitten = 4 feet

7 cats + 7 x 7 kittens = 49

then 7 cats + 49 kittens = 56 all

then 56 x 4 feet assumed that they have a normal sizes

56 x 4 = 224

224 x 7 sacks = 1568 feet has it all...

2006-12-06 17:42:28 · answer #2 · answered by azer 1 · 0 0

you tricked the others by adding mice latter
with the mice
7 sacks
7 cats per sack
7 kittens per cat
7 mice per kitten
all with four paws ( feet ).
is 4(7^4) that equals 9604 paws and feet

[as long as this is not a farmers question and you mean 1 foot equal 12 inches, in which case farmers 100 pound sacks are about 1 foot wide so that would be seven feet in a row]

2006-12-06 22:58:08 · answer #3 · answered by i_m_f_2009 2 · 0 0

7*7 = 49 cats in all
7*49=343 kittens

49*4 + 343*4=1568 feet

2006-12-06 17:34:34 · answer #4 · answered by Anonymous · 0 0

there are 49 cats and 343 kittens. every cat and every kitten has 4 feet, so the total number of feet is 49*4 + 343*4 = 1568 feet.

2006-12-06 17:34:06 · answer #5 · answered by need help! 3 · 0 0

7 sacks x (7 cats/sack) x (7 kittens/cat) x (4 feet/kitten) +
7 sacks x (7 cats/sack) x (4 feet/cat) =

7x7x7x4 + 7x7x4 = 1372 + 196 = 1,568 feet

2006-12-06 17:37:30 · answer #6 · answered by Jim Burnell 6 · 0 0

Wow that is a troublesome question. What grade of math homework is this reason it is difficult and that i'm in Geometry Honors. i imagine the smallest quantity of bats interior the cave is 9. i got here upon that 2 ought to ensure out of their accurate eye and four couldn't see out of the left so 2 of those 4 ought to in elementary words see out of their accurate and the different 2 were blind. Then if 3 ought to ensure out of their left eye and 5 couldn't see out of their accurate that means that 3 ought to easily see out of the right eye and the different 2 are completely blind. So 4 were completely blind and there have been 9 bats interior the cave. it is what i got here upon. i wish that is sweet and it helped get the homework performed.

2016-11-30 06:12:50 · answer #7 · answered by ? 4 · 0 0

very easy they are 7^3 *4 = 1372 feet

2006-12-06 17:36:18 · answer #8 · answered by maussy 7 · 0 0

4... the two people carrying the 7 sacks
2.. the person carrying the 7 sacls???

or none./. their all tied up in a wheel barrow?

2006-12-06 17:37:30 · answer #9 · answered by --strangel-- 1 · 0 0

252 feet with the mice

2006-12-06 17:44:53 · answer #10 · answered by Guess 3 · 0 0

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