Two coins and one six-sided number cube are tossed together.
What is the probability of getting two heads and a four?
2006-12-06 17:21:38 · 4 answers · asked by Jake D 2 in Science & Mathematics ➔ Mathematics
1/2 x 1/2 x 1/6 = 1/24
2006-12-06 17:23:08 · answer #1 · answered by Scythian1950 7 · 0⤊ 0⤋
probability of getting a head on one coin * probability of getting a head on the second coin * probability of getting a four on the cube
= 1/2 * 1/2 * 1/6
= 1/24 (answer)
2006-12-07 01:23:55 · answer #2 · answered by Anonymous · 1⤊ 0⤋
The probability of all three events occuring is equal to the product of the probablities of each individual occurence. That is:
P= 1/2 (the probability of the first coin being heads) * 1/2 (the probability of the other coin being heads) * 1/6 (the probability of rolling a 4
Multiply them together, and you get:
P= 1/24
2006-12-07 01:26:14 · answer #3 · answered by Robert R 2 · 0⤊ 0⤋
Probability of getting heads once: 1/2
Probability of getting heads twice: 1/2 * 1/2 = 1/4
Probability of getting a 4 on a 6-sided die: 1/6
Probability of both happening: 1/4 * 1/6 = 1/24
2006-12-07 01:24:32 · answer #4 · answered by Jim Burnell 6 · 0⤊ 0⤋