sequence (need to put in formula needed step please)?

Question

1. t1=6
2. t2=10
3. t3=14
4. t1=3
5. t2=5
6. t3=7

Answer 1

I'm assuming these are two sequences:
6, 10, 14...
and
3, 5, 7...

PROBLEM 1:
6, 10, 14...
t(1) = first term = 6
d = the difference between terms = 4
t(n) = t(0) + d(n-1)
t(n) = 6 + 4(n-1)
t(n) = 4n + 2

PROBLEM 2:
3, 5, 7...
t(1) = 3
d = 2
t(n) = t(0) + d(n-1)
t(n) = 3 + 2(n-1)
t(n) = 2n + 1

Answer 2

A quick hint, 6, 10, and 14 are twice as much as 3, 5, and 7.

Answer 3

t1=6
t2=10
t3=14
t2-t1=t3-t2=4
therefore common difference d=4
so the sequence will be
6,6+4+6+4+4,6+4+4+4 and so on
=>6+(0)*4,6+(1)4,6+(2)4+....,
.............................6+(n-1)*4
so the formula,generalising ,is tn=a+(n-1)*d
which will work out to tn=6+(n-1)*4

similarly for the second set of values
tn=3+(n-1)*2

Answer 4

I'm not sure what you're asking. It looks like a simple "divide by 2" transformation.