ok i have a few problems i need the answers to, i dont need explanations.
1) -(x-3) - 4(x-1) = 22
2) a(b-a to the power of zero)(-2a - b) x= -2, b= -3
3) (-3x - y squared) (-y-x) (3x) x= -2 y= -4
2006-12-06 15:12:53 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1) 1x + 3 - 4x + 4 = 22
-3x = 22 - 7
-3x = 15
-x = 15/3
x = -5
2006-12-06 15:16:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1) Distribute and solve for x.
-x + 3 - 4x + 4 = 22
-5x = 15
x = -3
2) Not sure what you mean by (b-a to the power of zero). If it is (b-a)^0 then that = 1. Also not sure what you mean by x = -2, b = -3. Is it part of the equation or not?
3) Just substitute x and y.
(-3(-2) - (-4)^2)*(-(-4)-(-2))*(3(-2))
= -22*6*-6
= 792
2006-12-06 15:14:46 · answer #2 · answered by thingstealer 2 · 0⤊ 0⤋
Alright, first replace all you variables (letters) with the numbers replacing them. Then you want to simplify and solve. The answers I got were as follows:
A: -3
B: 42
C: -18
I hope this helps you and I hope that you also learn how to solve these. Remember always ask for help if you need it.
2006-12-06 15:32:56 · answer #3 · answered by TroubleMaker 1 · 0⤊ 0⤋
Fvck
2006-12-06 15:26:04 · answer #4 · answered by xxxxxxxxxxxxxxxxxxxxxxxx 2 · 0⤊ 1⤋
(x-3)+4(x-1)=(-22)
x-3+4x-4=(-22)
5x-7=(-22)
5x=(-22+7)
5x=(-15)
x=(-3)
2006-12-06 15:20:32 · answer #5 · answered by SSS 3 · 0⤊ 0⤋
sorry
2006-12-06 15:20:34 · answer #6 · answered by LadyOreo 4 · 0⤊ 1⤋