Nitrogen can react with hydrogen to produce ammonia How many moles of nitrogen will be needed to produce 0.48 mol of NH3
2006-12-06 14:23:28 · 3 answers · asked by Mia16 3 in Science & Mathematics ➔ Chemistry
The reaction is N2 + 3H2 ---> 2NH3
Therefore, 1 mole of Nitrogen is need to make 2 moles of NH3.
Making it a 1:2 ratio.
So, you would need .24 moles of N to produce .48 moles of NH3.
2006-12-06 14:31:51 · answer #1 · answered by Zully 3 · 0⤊ 0⤋
For every mole of N you will need 2NH3 (as shown below).
1N2+3H2--------->2NH3
in this reaction every 1 mol of N makes two mols of NH3. So the ratio between the two substaces is 1 mol per 2 (1:2).
So you would multiply 0.48x(1/2) and get .24 mols.
And you would get .08 mols of Hydrogen.
2006-12-06 22:24:58 · answer #2 · answered by S 4 · 0⤊ 0⤋
N2 + 3H2 --> 2NH3
.48 mol NH3 ( 1 mol N2 / 2 mol NH3) = ?
2006-12-06 22:25:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋