2006-12-06 14:16:46 · 4 answers · asked by katie 4 in Science & Mathematics ➔ Mathematics
5^(2x+1) =10
lg 5^(2x+1) =lg10
(2x+1) lg5 = lg 10
2x+1= lg10/lg5
2x= (1/lg5)- 1 since lg10=1
x=[(1/lg5)-1] / 2
2006-12-06 14:23:53 · answer #1 · answered by mr warlords 2 · 0⤊ 0⤋
5^(2x+1) =10
(2x+1) ln 5=ln 10
2x+1=ln 10 / ln 5
2x=ln 10/ ln 5-1
x=(ln 10/ ln 5 -1)/2=0.2153
2006-12-06 22:41:41 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
5^(2x + 1) = 10
(2x + 1)ln(5) = ln(10)
2xln(5) + ln(5) = ln(10)
2xln(5) = ln(10) - ln(5)
2x = (ln(10) - ln(5))/(ln(5))
x = (ln(10) - ln(5))/(2ln(5))
x = (ln(10/5))/(2ln(5))
x = (ln(2))/(2ln(5))
ANS : x = (ln(2))/(2ln(5)) or (ln(2))/(ln(25))
they both mean the same thing.
2006-12-06 23:16:38 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
x = 0.21534
2006-12-06 22:34:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋