how can i solve this math quadratic question?

Question

please help this, seems to confuse me,

3X^2=2(X+1)

Help is really appreciated, along with the steps. thanks!!!

Answer 1

Your first step is to expand out the right hand side.

3x^2 = 2x + 2

Now, bring everything to the left hand side, resulting in a right hand side equal to 0.

3x^2 - 2x - 2 = 0

Plug these values into the quadratic formula.

x = [2 +/- sqrt(4 - 4(3)(-2)) ]/6
x = [2 +/- sqrt(30)]/6

Answer 2

First, lets factor the right side of the equation:

3x^2=2x+2

Now move the right side of the equation to the left:

3x^2-2x -2=0

Now you can factor it using either the quadratic equation where A is 3, B is -2, and C is -2

Answer 3

distribute the 2 to the X and the 1 on the right side, then shift them over to get 3X^2 - 2X - 2

Answer 4

arrange the equation into its general form
ax^2 + bx + c = 0
by subtracting 2x+2 from both sides
then use the quadratic equation
and find solution: x = [1 +/- sqrt(7)]/3

Answer 5

multiply the 2 to(x+1) then u get 3x^2=2x+1 then subtract the 2 from both sides -2x -2x which leaves u x^2=1 then square root x to get rid of ^2 which leaves u x=square root 1

Answer 6

if the "^2" is to the second power
than
3x^2=2(x+1)
3x^2=2x+2
-2x -2x
x^2=2
square root x^2= square root of 1
x= square root of 1

Answer 7

3x^2 = 2(x+1)
3x^2 = 2x + 2
3x^2 - 2x - 2 = 0

Compare the above equation to:
ax^2+bx+c=0
where
a = 3
b = -2
c = -2

using Quadratic Formula
..............________
......-b ±√b^2 - 4ac
x = ------------------------
...............2a

Substitute the values of a, b and c into the formula above and you'll get your value for x.

Answer 8

3X^2=2(X+1)
3X^2 = 2x+2
3X^2 - 2x - 2

Answer 9

Maybe if you would pay attention in class you would know how to solve this problem