(x^4+x^2+5)/(x^2+2)?

Question

algebra II question

Answer 1

You have to use long division. It's hard to do on this limited interface, but I'll do my best.

x^2 + 2 (into) x^4 + x^2 + 5

First, you determine how many times x^2 goes into x^4. The answer is x^2. So you'd write an x^2, multiply x^2 with (x^2 + 2), and subract.

(x^4 + x^2) - (x^4 + 2x^2) = -x^2

Bring down the 5, to get (-x^2 + 5)

Now, you'd calculate how many times x^2 goes into -x^2. The answer is -1. So you'd then multiply -1 by (x^2 + 2), and you end up subtracting.

(-x^2 + 5) - (-x^2 - 2) = 7

7 is your remainder, and x^2 - 1 is your dividend.

So your answer is 7/(x^2 + 1) + (x^2 - 1)

Answer 2

(x^4+x²+5)/(x²+2)
Answer: x different of -2
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Answer 3

x^2 - 1 + 7/(x^2+2)

note that the 7/(x^2+2) is it's own fraction, it's not the whole thing over that.

Answer 4

(x^4+x^2+5)/(x^2+2)=? and solving for x?

Answer 5

god, if youre not going to help him, dont waste his time typing this pointless spam.
(x^4+x^2+5)/(x^2+2)
= x^6+5/x^2+2
=x^4+3

Answer 6

strange... i have that exact same problem for homework, too bad im failing algebra 2

Answer 7

div is x^2-1
remainder is 7

Answer 8

well u retarted. u have to figuer out x. soo if u dont no wat x is thennn heres the answer

xxxx+xx+5 over xx+2

hehe your gay.

Answer 9

umm no, you're retarded because you can't even spell retarded

Answer 10

THATS EASY!