A light bilb consume 3600 watts-hour per day. How many long does it take to consume 15600watt-hour?
Day_?and Hour_?
2006-12-06 13:04:36 · 6 answers · asked by spongebizze 2 in Science & Mathematics ➔ Mathematics
Here's how to do it:
Try doing it first.... You'll learn more.
we know that 3600 x 5 is too much, because thats over 15000 kwh.
so its not 5 days. 4 days = 14,400 kwh, which isnt enough...
so we need 1200 more kwh, which, if you divide 3600/1200, is 1/3. what is one third of a day (24 hours in a day)? (0.33 x 24)
8 hours. So it's 4 days 8 hours.
answer:
4 days 8 hours
btw, MW is WRONG
2006-12-06 13:10:17 · answer #1 · answered by DaveEngel1 2 · 0⤊ 0⤋
If I understand you question right then:
15,600/ 3600 = 4 1/3 days
If you take 24 hours in one day and night then:
4 1/3 * 24 = 104 hours.
2006-12-06 21:13:22 · answer #2 · answered by Brenmore 5 · 0⤊ 0⤋
4 days and 3 hours
2006-12-06 21:06:55 · answer #3 · answered by MW 2 · 0⤊ 0⤋
Err.
15600 watt hour
divided by 3600 watt hour = 4.33 days.
In otherwords
4 days. 4 hours.
(.33*12hours in a day= 4 hours)
2006-12-06 21:12:26 · answer #4 · answered by jonolsonroll2000 2 · 0⤊ 0⤋
4.33333333 days
2006-12-06 21:06:38 · answer #5 · answered by tim_house2003 3 · 0⤊ 0⤋
4.333333
2006-12-06 21:34:24 · answer #6 · answered by sam 3 · 0⤊ 0⤋