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-24bc^4 - 40bc^3 - 32bc^2

2006-12-06 12:28:14 · 4 answers · asked by 988898.23225 1 in Science & Mathematics Mathematics

4 answers

You would have to pull out the biggest term. What is common to each of them? First off, there's the negative sign. Next, what is common to 24, 40, and 32? The answer to that is 8. Next, what is common between the variables? Looks like a single b and a c^2. So we pull out -8bc^2 and get

-8bc^2 [ 3c^2 + 5c + 4]

This doesn't factor any further.

2006-12-06 12:33:25 · answer #1 · answered by Puggy 7 · 0 0

First factor out the common monomial, which is -8bc^2
-8bc^2(3c^2 + 5c + 4)

the trinomial factor cannot be further factored because it is prime. According to the determinant (b^2 -4ac) this trinomial has only imaginary roots.

2006-12-06 20:35:41 · answer #2 · answered by Marcella S 5 · 0 0

factor out a -8bc^2 so you get -8bc^2(4c^2+5c+4).
thats as simple as you can get it.

2006-12-06 20:38:14 · answer #3 · answered by Jessie 2 · 0 0

-8bc^2(3c^2+5c+4)

2006-12-06 20:32:44 · answer #4 · answered by jerryst316 2 · 0 0

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