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A race car has a mass of 710 kg, it starts from rest and travels 40 meters in 3 seconds. The car is uniformly accelerated during the entire time. What is the net force acting on the car?

2006-12-06 12:04:12 · 4 answers · asked by w_xsoadx_w 2 in Science & Mathematics Physics

4 answers

Force = mass * acceleration

Acceleration = [Velocity (Final) - Velocity initial)]/time

Vav = 40m/3sec = [V( final) + Velocity (initial)]/2, we know Vinitial is 0, therefore final velocity 80m/3sec

acceleration =(Vf - Vi)/time = 80m/3sec/3sec = 80m/9sec^2

(sorry no calculator)

Force = 710 kg * 80meters/9sec^2

please check for errors, and simplify

be back

2006-12-06 12:09:06 · answer #1 · answered by Anonymous · 0 0

To complicated further...you're able to desire to locate the acceleration. because of the fact the fee doubles in 5 sec, that's the thank you to define the acceleration. First convert 36 km/h into km/sec. This will become 0.01 km/s the fee doubles, subsequently cases it via 2, and that's finished over 5 seconds, consequently divide the two via 5 A=(2*0.01)/5 = 0.004 m/s^2 F=MA=one thousand*0.004= 4 N (Newtons) That guy decrease than me is appropriate...I knew i replaced into off on instruments someplace.

2016-12-11 03:42:15 · answer #2 · answered by ? 4 · 0 0

AbeLincol... could have used a more direct approach to getting acceleration:
s = (1/2)*a*t^2

Same answer tho.

2006-12-06 12:41:25 · answer #3 · answered by sojsail 7 · 0 0

ummm gravity?

2006-12-06 12:06:58 · answer #4 · answered by Anonymous · 0 1

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