find the equation of the tangent line to the curve y = ln(x^2-3) at (2,0)?

Question

and thanks again to stephen if you help me out with this one hah

Answer 1

y'=(2x)/(x^2-3)

at x=2
y'=4/1=4
so the slope is 4 and we know the line goes through (2,0)
0=4(2)+b
b=-8
y=4x-8