Im really stuck on these three questions. Solve for what C would be. 1. F=9/5c+32 Solve for y. 3x+4y=1 Solve. 3. 4/3d-4=1/6
2006-12-06 11:12:28 · 7 answers · asked by steelerxfan 2 in Science & Mathematics ➔ Mathematics
F = (9/5)C + 32
F-32 = (9/5)C
(F-32)/(9/5) = C
(5/9)(F-32) = C
3x+4y = 1
4y = 1-3x
y = (1-3x)/4
(4/3)d - 4 = 1/6
(4/3)d = 1/6 + 4 = 25/6
d = (25/6)/(4/3) = (25/6)*(3/4) = 25/8
Hope that helps ☺
Doug
2006-12-06 11:19:24 · answer #1 · answered by doug_donaghue 7 · 0⤊ 1⤋
C= 5/9(f-32)
Y = (1-3x)/4
d = 3/4(1/6 +4) = 3/4 x 25/6 = 25/8
2006-12-06 19:16:37 · answer #2 · answered by panenka_chip 2 · 0⤊ 1⤋
1. 5F=9C+160
9C=5F-160
C=5/9F-160/9
(converting centigrade to farenheit)
2. 4y=1-3x
y=1/4+3/4x
3. 4d-12=2/3
4d=2/3+12
d=25/8
2006-12-06 19:32:34 · answer #3 · answered by Paul H 2 · 0⤊ 0⤋
(f-32)5/9=c
(1-3x)/4
25/8
2006-12-06 19:18:57 · answer #4 · answered by Anonymous 2 · 0⤊ 0⤋
as far as i can figure the answers are as follows, but you might want to check that for yourself:
C=5/9f + 160/9
y=1/4 - 3/4x
d=25/8
2006-12-06 19:26:09 · answer #5 · answered by lex 1 · 0⤊ 0⤋
The first exercise shows you how to transform oF (Fahrendheits degress) into oC (Celsius degress)
Ana
2006-12-09 21:30:42 · answer #6 · answered by Ilusion 4 · 0⤊ 0⤋
I am not good at math. I am able to count my blessings.
2006-12-06 19:15:38 · answer #7 · answered by Kathrina C 2 · 0⤊ 1⤋