What would the attractive force be if they were one-half as far apart?
5 N
10 N
40 N
80 N
2006-12-06 11:08:45 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
the formula is exponential.... As answered by a few before me, I too agree. 80 newtons
2006-12-06 11:17:23 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Force of gravity is defined as
F = G*M*m/r^2
where G is the gravitational constant, M and m are the masses of the objects and r is the distance. Since r is squared, halving the distance would increase the force by 4 times, so 80 N
2006-12-06 11:12:40 · answer #2 · answered by John P 2 · 3⤊ 0⤋
The force is inversely proportional to the square of the distance, so it would quadruple. The answer is 80 N.
2006-12-06 11:12:55 · answer #3 · answered by computerguy103 6 · 1⤊ 0⤋
80. Those are large spacecraft...
2006-12-06 11:17:10 · answer #4 · answered by Steve-o 3 · 0⤊ 0⤋
I don't know. I will pick 40N
2006-12-06 11:12:22 · answer #5 · answered by Anonymous · 0⤊ 1⤋