What is the correct partial derivative with respect to y for the function f(x,y)=x^2sin(3x)?
I'm thinking it is x^2cos(3x), but I'm not sure.
If you guys could give me any advice I'd reeeeaaalllyy appreciate it
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2006-12-06 11:08:38 · 5 answers · asked by cheezo12 1 in Science & Mathematics ➔ Mathematics
WHOOPS! I meant f(x,y)=x^2sin(3xy)
2006-12-06 12:13:51 · update #1
you got it
2006-12-06 11:10:33 · answer #1 · answered by Anonymous · 0⤊ 1⤋
No, its 0. With respect to y, that whole thing is just a constant; and a constant differentiates to 0.
Edit - ok, now that you've fixed the question :)
x^2sin(3xy)
The x^2 on the front is a constant, so we leave it there.
We have sin(constant * y), which differentiates to constant * cos(constant * y).
So overall we get x^2 * 3x * cos(3xy)
= 3x^3 cos(3xy).
2006-12-06 19:11:58 · answer #2 · answered by stephen m 4 · 0⤊ 0⤋
0. Look at it, there's no y term. It's just like taking the derivative of a constant as there's no dependence on y.
2006-12-06 19:14:44 · answer #3 · answered by joker 2 · 0⤊ 0⤋
Since the function has no y variable the f(x,y) is meaningless. Your solution is a derivative based on variable x not y.
2006-12-06 19:19:19 · answer #4 · answered by wealthmaster 3 · 0⤊ 1⤋
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2006-12-06 19:11:52 · answer #5 · answered by Nashyiah S 1 · 0⤊ 1⤋