2*3*3*13
2006-12-06 10:28:32
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answer #1
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answered by computerguy103 6
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Factors Of 234
2017-01-09 19:07:25
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answer #2
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answered by Anonymous
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Since it's even. one such factor is 2, leaving 117. Proof by nines [sum of the digits is a multiple of 9] shows that 9 is a factor, leaving 13, which is prime. So the complete factorization is 2 x 3 x 3 x 13.
2006-12-06 10:31:16
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answer #3
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answered by Anonymous
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2 * 3 * 3 * 13 = 234
1 * 234 = 234
2 * 117 = 234
3 * 78 = 234
6 * 39 = 234
9 * 26 = 234
13 * 18 = 234
2006-12-06 10:38:09
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answer #4
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answered by Anonymous
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234/2=117/3=39/3=13
so2*3*3*13
2006-12-06 10:30:01
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answer #5
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answered by raj 7
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13, 3^2 and 2.
2006-12-06 10:29:17
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answer #6
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answered by zee_prime 6
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wow there are alot:
1,2,3,6,9,13,18,26,
39,78,117,234
(you get the factors by figuring out which numbers will multiply out to get 234)
2006-12-06 10:30:28
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answer #7
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answered by brookbabe90 5
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Just divide by 2 then 3 then 4 etc.. You get 2 and 117. 3 and 78 etc
{1,234},{2,117},{3,78},{6,39},{9,26},{13,18}
You can stop when the number you divide by becomes bigger than the number u get.
2006-12-06 10:31:12
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answer #8
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answered by Michael W 2
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1,2,3,6,9,13,18,26, 39,78,117,234.. i think that's right.
2006-12-06 10:53:36
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answer #9
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answered by Anonymous
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1,2,3,6,9,13,18,26,39,78,117
,234
2006-12-06 10:29:16
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answer #10
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answered by Anonymous
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