i need to solve the absolute value equation.
[k]-3=2k
i know one is -3=k, but what is the other??
thanks help is appreciated,!!
2006-12-06 10:24:59 · 7 answers · asked by BLUEEEE 1 in Science & Mathematics ➔ Mathematics
first move 3 to the other side
[k]=2k+3
next break it into two possible equations and solve for k
k=2k+3
-k=3
k=-3
or
-k=2k+3
-3k=3
k=-1
2006-12-06 10:29:25 · answer #1 · answered by alikat4392 4 · 0⤊ 0⤋
Just rewrite as two equations:
k - 3 = 2k (you solved this one already) and
-k - 3 = 2k
2006-12-06 18:27:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
k-3=2k
-3=k <---answer 1
and the other one is
-k-3=2k
-3=3k
-1=k <---answer 2
2006-12-06 18:30:26 · answer #3 · answered by L_Bizzy25 2 · 0⤊ 0⤋
all i know is that k=-3 is wrong
its probaly k=-1
[-1]-3=2(-1)
1-3=-2
-2=-2
2006-12-06 18:27:53 · answer #4 · answered by Luna 4 · 0⤊ 0⤋
I really don't think k = -3
2006-12-06 18:33:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋
-k-3=2k
3k=-3
k=-1
2006-12-06 18:27:14 · answer #6 · answered by raj 7 · 0⤊ 0⤋
what math is this equation
2006-12-06 18:28:32 · answer #7 · answered by aninjashinobi25 1 · 0⤊ 0⤋