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8 answers

For a circle, a = pi*r².
For a half circle, it is half that.

a = 0.5*pi*(50/2)²
a = 981.75m²

2006-12-06 10:23:38 · answer #1 · answered by computerguy103 6 · 0 0

Recall that the formula for a (whole) circle is

A = pi * r^2

Since we can get the radius from the diameter (it's half of it),
r = 25

Therefore,

A = pi * (25)^2 = 625pi

Now, this is the area of the WHOLE circle. We want the area of 1/2 of it. So we just cut the area in half

(1/2) A = (1/2) 625pi
(1/2) A = (625pi) / 2

2006-12-06 18:22:30 · answer #2 · answered by Puggy 7 · 0 0

the area of a circle is pi * r^2 where r = 25m (1/2 the diameter)

25^2 = 625 and pi = 3.14159 so a circle with diameter 50m is 78.5398 m

the half circle is half that so your answer is 39.27 m

2006-12-06 18:29:51 · answer #3 · answered by Anonymous · 0 0

Consider a full circule with diameter 50m. Its area is pi x r^2 where r is the radius. r = d/2, therefore area of full circle = pi x d^2/4.

Area of full circle in your case is 3.1416 x 50^2 / 4 = 625 x pi

Area of half circle is half of area of full circle. Area of haf circle is 312.5 x pi.

2006-12-06 18:29:10 · answer #4 · answered by Anonymous · 0 0

Remember, the formula for the area of a circle is pi times radius squared. So, the radius is 25m, meaning you multiply 25 squared (625) by pi. However, since its a semi-circle, all you need to do is divide the area by half.

2006-12-06 18:27:06 · answer #5 · answered by darthfroehlious 2 · 0 0

Area is pi r^2. The radius is just half the diameter so it sould be
pi (25)^2=1963.5/2=981.7

2006-12-06 18:23:08 · answer #6 · answered by Michael W 2 · 0 0

I'm pretty sure its (1/2 of the diameter)squared times pi
Then divide the entire thing by 2 because it is a half circle
It should be 312.5 pi meters squared

2006-12-06 18:22:41 · answer #7 · answered by Luna 4 · 0 0

Haven't you already asked this question? There were some good answers showing you how to find the area and pointing out that 25 squared is 625.

2006-12-06 18:23:55 · answer #8 · answered by panenka_chip 2 · 0 0

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