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Maximizing Power Output of a battery

Formula is: P= VI - RI^2

V= Force in Volts R= Resistance I=Current

V=12 R=0.5

2006-12-06 09:40:55 · 2 answers · asked by petswodahs 1 in Science & Mathematics Mathematics

2 answers

So you want to maximise 12I - 0.5I^2?
Differentiate to get 12 - I = 0, so I = 12.

So power = 12*12 - 0.5*12^2 = 72W.

2006-12-06 09:55:37 · answer #1 · answered by stephen m 4 · 0 0

so P = -0.5 I ^2 + 12 I
this is a downward face parabola. the max occurs when
I = -12 / -1 = 12
if I = 12, then P = 72

2006-12-06 17:56:28 · answer #2 · answered by socialistmath 2 · 0 0

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