Clearing Fractions, This is a doozy?

Question

problem 3x/2 + 2 = X/2 + 4

step 1. (2) 3x/2 + 2 = (2) x/2 + 4
step 2. 3x + 4 = x + 8
step 3. 3x - x = 8 - 4
step 4. 2x = 4
step 5. x = 2
I dont understand how to clear away the fractions....steps 2-5 I understand

Answer 1

Step one is written incorrectly. To clear the fractions you want to multiply both sides of the equation by the lowest common denominator, which is 2.

2(3x/2 +2) = 2(x/2 +4)
notice the parentheses are around both sides of the original equation. Now distribute the 2

2(3x/2) +2(2)= 2(x/2) +2(4)

when you simplify this you will get step 2

I hope this helps

Answer 2

problem 3x/2 + 2 = X/2 + 4

step 1. (2) 3x/2 + 2 = (2) x/2 + 4
step 2. 3x + 4 = x + 8
step 3. 3x - x = 8 - 4
step 4. 2x = 4
step 5. x = 2
for clearing away the fractions you must get rid of the denominator
here the denomonator is 2
so multiply throughout by 2

Answer 3

step 2. 3x + 4 = x + 8
step 3. 3x - x = 8 - 4 - Subtract x and 4 to put varibles on 1 side and numerals on the other
step 4. 2x = 4 - 3x-x= 2x, 8 - 4 = 4
step 5. x = 2 - divide both sides by two and youve got your answer

Answer 4

Since the only thing you have on the bottom of a fraction is 2, they've just multiplied everything by 2.
3x/2 times 2 = 3x.
2 times 2 = 4
x/2 times 2 = x
4 times 2 = 8
So it turns into 3x + 4 = x + 8.

Answer 5

Well, if you are just talking about step 1, it is all about multiplying both sides by 2.
2 is the common denominator between both fractions on each side.
It is easy if the fractions have the same denominator. Just multiply both sides by that denominator.

If they don't have the same denominator on each side, you have to find a factor that both of the denominators go into. The easiest is to multiply the two numbers that are in the denominators and multiply both sides by their product.
For example, if I had 3/4 and 2/3, I would multiply both sides by 12 in order to eliminate the fractions.