a. 12.46 b. 18.33 c. 20.88 d. 32.17
2006-12-06 08:38:18 · 5 answers · asked by hnbjn 1 in Science & Mathematics ➔ Mathematics
You can use Heron's formula, which says the area is sqrt(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2.
So s = (5+8+11)/2 = 12, and we get sqrt(12*7*4*1) = 18.33.
2006-12-06 08:44:48 · answer #1 · answered by stephen m 4 · 1⤊ 0⤋
Use the formula
Area = sqrt ( s * (s-a) * (s-b) * (s-c) )
where s = (a+b+c)/2.
Then s = (5+8+11)/2 = 24/2 =12.
So Area = sqrt ( 12 * (12-5) * (12-8) * (12-11) )
= sqrt ( 12 * 7 * 4 * 1) = sqrt(336) = 18.33
2006-12-06 08:49:47 · answer #2 · answered by David Y 5 · 0⤊ 0⤋
i'd take the log of both area. Log 5^x = log 24 then bypass the x in the front of the log. Xlog5 = log24 then divide all aspects by utilizing log5 so that you x nicely worth typically is the answer of log24/log5. that you need to round this to 2 decimal places.
2016-11-24 19:28:47 · answer #3 · answered by ? 4 · 0⤊ 0⤋
s=(a+b+c)/2
=(5+8+11)/2
=12
area=rt12*(12-5)(12-8)(12-11)
=rt12*7*4*1
=rt336
=18.33
2006-12-06 08:43:58 · answer #4 · answered by raj 7 · 1⤊ 0⤋
you need to tell us what is the base, and what is the height the equation is a=(B*H)1/2
where b=base
and h =height
2006-12-06 08:41:34 · answer #5 · answered by Zachary W 2 · 0⤊ 2⤋