2006-12-06 08:34:00 · 6 answers · asked by Math Freak 1990 1 in Science & Mathematics ➔ Mathematics
Surface Area of a Cylinder = 2 pi r ^2 + 2 pi r h
use h = 14.6 cm and r = 6.3 cm
this comes to 827 cm
(how can it be 8 cm as in 1st answer? the height itself is 14.6 cm)...lol now he changed it.
2006-12-06 08:39:52 · answer #1 · answered by pkababa 4 · 0⤊ 1⤋
The total surface area is the area of 2 circles and the lateral area, which is found by multiplying the circumference of teh circle by the height of the cylinder.
2(3.14)(6.3)(6.3) + 3.14(12.6)(14.6)
249.2532 + 577.6344
826.8876 square cm
do you need to round it?
2006-12-06 16:47:44 · answer #2 · answered by mom 7 · 0⤊ 0⤋
You have to add the areas of the cylinder bases and circumference.
14.6*6.3*2*pi=183.96*pi
6.3^2*pi*2=79.38*pi
183.96*pi+79.38*pi=263.34*pi=
827.307 cm.
2006-12-06 16:36:51 · answer #3 · answered by er_i_m 4 · 0⤊ 1⤋
Hi. Pi times radius square, times 2 for the ends. 2 Pi diameter times height for the OD. add the three.
2006-12-06 16:37:41 · answer #4 · answered by Cirric 7 · 0⤊ 1⤋
find the area of the base and multiply it by 2
2(pi(r)^2)
79.38(pi)
find the circumference of the circle and multiply that by the height
2(pi)rh
183.96(pi)
add these two numbers together to get the surface area of the cylinder
79.38(pi) + 183.96(pi)
263.34(pi)
ANSWER
263.34(pi) square cm
2006-12-06 16:46:02 · answer #5 · answered by trackstarr59 3 · 0⤊ 0⤋
Pi x R x 14.6=577.927cm.
2006-12-06 16:45:57 · answer #6 · answered by dale b 1 · 0⤊ 1⤋