Hey Everyone I missed class today because my friend was in the hospital and I missed the lesson and i was hoping someone could help me thanks! oh and also if you could show me how you got it that would be great so I can learn how to! :)
1. Express the trinomial as the product of its greatest monomial factor and another polynomial.
12^3y^2 - 8x^2y^2 + 16x^3y
2. Factor Completely
2x^2y + 12xy + 18y
3. Write the product as a polynomial.
(2a - 3b)^2
^ means squared!
Thanks!!
2006-12-06 08:00:46 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1) I'm going to guess that 12^3y^2 was a typo for 12x^3y^2.
Just look for the common parts of each term.
Firstly, the constant parts: 12, -8, 16. Those all share a factor of 4.
The x parts: x^3, x^2, x^3. Those all share a factor of x^2.
The y parts: y^2, y^2, y. Those all share a factor of y.
So we take 4x^2 y out the front, and divide each term by that to see what we have left:
4x^2 y(3xy - 2y + 4x).
2.
Again, the constant parts share a factor of 2; there are no common factors of x, but there is a y. So take the 2y out the front:
2y(x^2 + 6x + 9).
Now you can recognise that you can actually factorise that quadratic in x - its a perfect square, so you get 2y(x+3)^2.
3.
(2a-3b)(2a-3b)
= 2a*2a - 2a*3b - 3b*2a + 3b*3b
= 4a^2 - 12ab + 9b^2.
2006-12-06 08:24:46 · answer #1 · answered by stephen m 4 · 0⤊ 0⤋
1. 12^3=1728
1728y^2-8x^2y^2+16x^3y
8y(216y-x^2y+2x^3)
2. 2y(x^2+6x+9)
2y (x+3)(x+3)
2y(x+3)^2
3. (2a-3b)(2a-3b)
FOIL
4a^2-12ab+9b^2
2006-12-06 16:27:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋