college algebra
2006-12-06 06:21:48 · 6 answers · asked by koka 1 in Science & Mathematics ➔ Mathematics
Raise both sides upon the base x:
x^(log[x] 64) = x^(-2)
64 = 1/x²
x² = 1/64
x = ±(1/8)
2006-12-06 06:24:28 · answer #1 · answered by Puzzling 7 · 1⤊ 1⤋
bring the 64 into left side and the equation become like this
x = 64 ^ -2
x = 1/square root of 64
x = 1/8
2006-12-06 06:25:57 · answer #2 · answered by f1fanz 2 · 0⤊ 0⤋
Again, in english:
x to what power gives us 64? -2
1. write it with exponents
2. solve for x
2006-12-06 06:24:49 · answer #3 · answered by Science nerd 3 · 0⤊ 0⤋
x^-2=64
1/x^2=64
x^2=1/64
x=1/8
2006-12-06 06:25:30 · answer #4 · answered by raj 7 · 0⤊ 0⤋
x^(-2) = 64
x = 1/8
2006-12-06 06:24:56 · answer #5 · answered by alia_vahed 3 · 0⤊ 0⤋
No.
2006-12-06 06:24:47 · answer #6 · answered by Anonymous · 0⤊ 1⤋