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A penny is dropped from the top of a building and takes 9 seconds to fall to the ground. What is the height of the building?




In the formula, d represents the distance an object falls, in feet, and t represents the time that an object falls, in seconds. Do not include units in your answer.

2006-12-06 02:13:03 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

distance = 4xtime of fall

time of fall = 9 seconds so...

d=4x9

2006-12-06 02:21:24 · answer #1 · answered by ilovejolie86 4 · 0 0

I'd need to know more about the environment of your question. For example, must we take air resistance into consideration? If yes, then the penny quickly reaches what is called "terminal velocity" and that velocity is constant. Once you know that velocity, then you multiply it by time to find total distance.

If you can disregard air resistance, then the penny accelerates constantly. on Earth, this gravitational acceleration is an increase of 9.8 m/s for every second of fall.

So, after 9 seconds, you penny hits the ground at a speed of 88 m/s. However, it has not been going at that speed during the fall so you cannot use a straightforward v*t equation.

Based on the wording of your question, it appears that the penny does attain terminal velocity and that velocity's measure is 4 units per second.

The second link gives some values for terminal velocity of pennies. Look near the end (in the Conclusion)

2006-12-06 10:25:35 · answer #2 · answered by Raymond 7 · 0 0

s = Vo(t) + 1/2 At^2
since initial velocity is 0, s = 1/2 At^2
A is acceleration ...32' / s^2

so its 1/2 * 32 * 9^2 =
16 * 81 = 1296'

2006-12-06 10:46:23 · answer #3 · answered by Brian D 5 · 0 0

This is a very simple question. Plug in your numbers and work it out... don't have other people do your work.

2006-12-06 10:16:50 · answer #4 · answered by Anonymous · 0 0

Dont outsource your homework...

2006-12-06 10:18:49 · answer #5 · answered by ashwin_hariharan 3 · 0 0

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