Factor completely 6x-66+xy-11y?

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2006-12-06 01:49:24 · 5 answers · asked by ME 3 in Science & Mathematics ➔ Mathematics

6x - 66 + xy - 11y

6(x - 11 + y(x - 11)

(6 + y)(x - 11)

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2006-12-06 02:24:25 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋

taking 6 common in (6x -66xy) and +y in (x-11)
then we get 6(x - 11) + y(x - 11)
therefore the factors are (6+y) (x - 11)

2006-12-06 10:02:58 · answer #2 · answered by beautifulocean 1 · 0⤊ 0⤋

(6+y)(x-11) is correct. The method is called factoring by grouping and is something to try when you have four terms in the polynomial.

2006-12-06 10:25:25 · answer #3 · answered by anr 3 · 0⤊ 0⤋

(y+6)(x-11)

2006-12-06 10:04:56 · answer #4 · answered by ash v 3 · 0⤊ 0⤋

(6x+1)(11y+1)....uh...i think :)

2006-12-06 09:59:40 · answer #5 · answered by The Kujinator 2 · 0⤊ 0⤋