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1
11
21
1211
111221
312211
13112211
1113212221
311312113211
132113111221131221
111312211331222113112211

2006-12-06 00:28:07 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

Each number (besides the initial one) describes the number before it like this:
1
one 1 (11)
two 1's (21)
one 2 and one 1 (1211)
one 1, one 2 and two 1's (111221)
three 1's, two 2's and one 1 (312211)
and so on...

2006-12-06 00:36:55 · answer #1 · answered by Bugmän 4 · 0 1

The next number is the one after the one before.

2006-12-06 00:30:52 · answer #2 · answered by Dazed 2 · 0 1

4

2006-12-06 00:37:59 · answer #3 · answered by Anonymous · 0 3

The method to answering this is:

1 this is one one -> 1 1
11 this is two ones -> 2 1
2 1 this is one two and one one -> 1 2 1 1
1 2 1 1 this is one one, one two and two ones
1 1 1 2 2 1

31 13 11 22 21 23 11 32 21 13 21 22 21

2006-12-06 00:32:52 · answer #4 · answered by anton3s 3 · 3 1

311311122212311322113212221

This is just saying that in the previous number there are:
3 1's followed by 1 3 followed by 1 1 followed by 2 2's etc

2006-12-06 00:52:52 · answer #5 · answered by ironduke8159 7 · 0 1

No-one noticed the deliberate mistake???!

1
11
21
1211
111221
312211
13112211 <-- this should be 13112221
1113212221
311312113211
132113111221131221
111312211331222113112211

so carrying on...

13112221
1113213211
31131211131221
13211311123113112211
11131221133112132113212221
and the 12th term would be
31131122212321121113122...
....11312113211

2006-12-06 00:46:03 · answer #6 · answered by Krop 2 · 1 2

Long if i had time id tell you the answer but the answers have 1s 2s and 3s in it

2006-12-06 00:37:14 · answer #7 · answered by uk_duggy_uk 3 · 0 2

The seventh line is wrong, so the question is pointless.

2006-12-06 10:09:17 · answer #8 · answered by mainwoolly 6 · 0 2

31131122212311322113212221

2006-12-06 00:41:11 · answer #9 · answered by socialistmath 2 · 0 1

31131122212311322113212221

2006-12-06 03:38:56 · answer #10 · answered by Anonymous · 0 2

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