2006-12-06 00:03:46 · 6 answers · asked by ME 3 in Science & Mathematics ➔ Mathematics
xy-4y+10x-40
y(x-4)+10(x-4)
(x-4)(y+10)
2006-12-06 00:11:50 · answer #1 · answered by raj 7 · 0⤊ 0⤋
xy + 10x - 4y - 40 = x(y+10) - 4(y+10) = (x-4)(y+10)
2006-12-06 09:31:37 · answer #2 · answered by yasiru89 6 · 0⤊ 0⤋
xy+10x-4y-40 = xy-4y +10x-40
=y(x-4) + 10(x-4)
=(x-4)(y+10) Ans
2006-12-06 08:21:46 · answer #3 · answered by ATS 2 · 0⤊ 0⤋
xy+10x+4y-40
= x(y+10)-4(y+10)
= (y+10) (x-4) :answer
2006-12-06 08:14:54 · answer #4 · answered by rupin27 2 · 0⤊ 0⤋
xy+10x-4y-40
x(y + 10) - 4(y+10)
(y+10)(x-4)
In factoring by grouping, you do it 2 terms at a time.
After that you will see a common term (y+10) in the above example.
Factorise this term out - and you get your answer !
2006-12-06 08:13:24 · answer #5 · answered by Matthew N 5 · 0⤊ 0⤋
First:
x(y + 10) - 4(y +10)
Then
(x - 4)(y + 10)
2006-12-06 08:13:54 · answer #6 · answered by MustangGT 2 · 0⤊ 0⤋